plz ans quickly dont have much time

Asked by 100.akash | 8th Apr, 2009, 04:11: PM

Expert Answer:

(d)t^2-15

two zeroes at t^2-15 = 0 i.e. t=15

(e)3x^2-x-4 = (3x-4)(x+1)

so zeroes when 3x-4=0 ==> x=4/3 and x+1=0 ==> x=-1

Answered by  | 9th Apr, 2009, 01:38: AM

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