CBSE Class 10 Answered
plz ans quickly dont have much time
Asked by 100.akash | 08 Apr, 2009, 04:11: PM
Expert Answer
(d)t^2-15
two zeroes at t^2-15 = 0 i.e. t=15
(e)3x^2-x-4 = (3x-4)(x+1)
so zeroes when 3x-4=0 ==> x=4/3 and x+1=0 ==> x=-1
Answered by | 09 Apr, 2009, 01:38: AM
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