Asked by garimasingh | 13th Oct, 2009, 12:41: PM
PQ ll BC
also, AD is median,
let AD meets PQ in E.
In triangles,APE and ABD
angle APE=angleABD...corr angles
angle A is common , so triangles are sim by AA rule.
simly by taking trangles AQE and ACD we get,
so from above eqns we get
but BD/CD=1 ... since AD is median
E is mid pt of PQ
AD bisects PQ.
Answered by | 14th Oct, 2009, 10:16: AM
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