pls solve
Asked by | 10th Mar, 2008, 06:16: PM
Expert Answer:
= integral sq root sinx/ cosx dx
now put cosx =t
we get -sinx dx= dt
therefore we have,
integral sq root sinx/ cosx dx = integral -sq root 1/t dt = -2t to the power 1/2
now put the value of t, we get the answer as
-2 sq root cosx.
Answered by | 11th Mar, 2008, 05:39: PM
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