pls solve

Asked by  | 10th Mar, 2008, 06:16: PM

Expert Answer:

= integral sq root sinx/ cosx dx

now put cosx =t

we get -sinx dx= dt

therefore we have,

integral sq root sinx/ cosx dx = integral -sq root 1/t dt = -2t to the power 1/2

now put the value of t, we get the answer as

-2 sq root cosx.

 

Answered by  | 11th Mar, 2008, 05:39: PM

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