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CBSE Class 11-science Answered

Pls solve.
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Asked by pb_ckt | 18 May, 2019, 11:03: PM
answered-by-expert Expert Answer
Option (1) is correct.
 
Given:
 
Mass of an acid = 90 gm
 
Molar mass of acid = 90 gm
 
Volume of base = 40 ml
 
Normality of base = 0.5 N
 
basicity of acid = ?
 
Milli equ of  acid = milli equ of base
 
 
N1V1 = N2V2 
 
We space know comma Normality space equals space fraction numerator Weight over denominator Eq. space wt space cross times Vol space in space litre end fraction fraction numerator Weight over denominator Eq. space wt space cross times Vol space in space litre end fraction cross times Volume space equals space straight N subscript 2 straight V subscript 2 fraction numerator 0.90 over denominator begin display style bevelled fraction numerator eq space wt over denominator straight n end fraction end style end fraction space equals space 0.5 cross times 20 cross times 10 to the power of negative 3 end exponent straight n space equals space fraction numerator space 0.5 cross times 20 cross times 10 to the power of negative 3 end exponent cross times 90 over denominator 0.90 end fraction space space space space equals space 1
 
Basicity of acid is 1.
 

Answered by Varsha | 20 May, 2019, 12:24: PM

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