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CBSE Class 10 Answered

pls solve this
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Asked by yashshirsath80 | 12 May, 2020, 10:03: AM
answered-by-expert Expert Answer
Question: Find the point on the y-axis which is equidistant from the points A(-4, 3) and B(5, 2).
Solution:
As the required point is on the y-axis, its x-coordinate will be 0.
Let P(0, a) be the required point.
As P is equidistant from the points A(-4, 3) and B(5, 2), we have
AP = PB
rightwards double arrow space square root of open parentheses negative 4 minus 0 close parentheses squared plus open parentheses 3 minus a close parentheses squared end root equals square root of open parentheses 0 minus 5 close parentheses squared plus open parentheses a minus 2 close parentheses squared end root rightwards double arrow space open parentheses negative 4 close parentheses squared plus open parentheses 3 minus a close parentheses squared equals open parentheses negative 5 close parentheses squared plus open parentheses a minus 2 close parentheses squared rightwards double arrow space 16 plus 9 minus 6 a plus a squared equals 25 plus a squared minus 4 a plus 4 rightwards double arrow space 25 minus 6 a equals 29 minus 4 a rightwards double arrow space 2 a equals negative 4 rightwards double arrow space a equals negative 2 H e n c e comma space P left parenthesis 0 comma negative 2 right parenthesis
Answered by Renu Varma | 12 May, 2020, 12:04: PM

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