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ICSE Class 10 Answered

Pls solve this The equal chords AB and CD of a circle with centre O,when produced,meet at P outside the circle.Prove that 1.PB=PD, 2.PA=PC.  
Asked by gsitabhanu24 | 31 Jan, 2019, 07:54: PM
answered-by-expert Expert Answer
Angles subtended by equal chords are equal.
So we have AC||BD, alternate angles test.
in triangle APC
BD ||AC
so
By BPT
AB/PB=CD/PD
now
AB=CD
so
PB=PD..............Ans1
Add AB on both sides
PB+AB=PD+AB
PB+AB=PD+CD........AB=CD
PA=PC...........Ans2
Answered by Arun | 01 Feb, 2019, 11:46: AM
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