pls solve this question The equation of motion of a projectile is y=12x-3/4x2(x square) the horizontal component of velocity is 3m/s the range of a projectile is?

Asked by Nidhi Mehrotra | 17th Sep, 2010, 12:18: PM

Expert Answer:

during the course of the flight, the vertical displacement is Zero. Now, y = 0 for x = 0,4 (By putting y = zero in the equation of the projectile).
 
Therefore, horizontal distance covered = 4 m = Range

Answered by  | 17th Sep, 2010, 03:16: PM

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