pls solve this integration ques

Asked by Kirandoon | 8th Jan, 2009, 12:22: PM

Expert Answer:

write sec4x as (1 + tan2x)2   now Let  tanx = t2 ====> sec2x dx = 2t dt   ====> (1 + tan2x) dx = 2t dt                  ====> dx = 2t dt / (1 + t4)         putting this into above expression we get     (1 + t4)2 2t dt / t (1 + t4)     which is same as  2 (1 + t4) dt  =  2  1+ t4 dt   =  t / 2 + 2 t5 / 5

so   sec4x  ÷   tanx       dx  =  tanx / 2 + 2 tan5/2x  / 5

Answered by  | 12th Jan, 2009, 06:28: PM

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