pls solve this.. 23x -29y=98,29x-23y=110
Asked by krishnabharathijuly
| 6th Apr, 2009,
02:47: PM
Expert Answer:
23x -29y=98...........(1)
29x-23y=110..........(2)
multiply eq(1) by 29 and eq(2) by 23 and then subtract
(-292 +232)y = 98x29-110x23
-312y = 312
y=-1
put this value in (1) we get x=3
Answered by
| 9th Apr, 2009,
02:20: AM
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