pls solve this.. 23x -29y=98,29x-23y=110

Asked by krishnabharathijuly | 6th Apr, 2009, 02:47: PM

Expert Answer:

23x -29y=98...........(1)


multiply eq(1) by 29 and eq(2) by 23 and then subtract

(-292 +232)y = 98x29-110x23

-312y = 312


put this value in (1)  we get x=3

Answered by  | 9th Apr, 2009, 02:20: AM

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