pls solve the problem

Position vector of particle-1 ,  m ,

velocity of particle-1 ,   m/s ,

Position of the particle-1 after 10 s =    m .............................(1)

Position vector of particle-2 ,    m,

Let velocity of particle-2 ,   m/s ,

Position of the particle-2 after 10 s is given by ,

 

m ......................(2)

If both particle collide after 10s, then their position vectors are equal

 

Hence by equating (1) and (2), we get,  2+10a = 8 ,  2+10b = -4 and (5+10c) = 7

 

Hence we get a = 0.6 ,  b = -0.6  and  c = 0.2

 

Hence velocity of particle-2 ,   m/s