Pls solve it.

Asked by pb_ckt | 1st May, 2019, 10:43: PM

Expert Answer:

 
Option (b) is correct.
Given:
 
1 gm of hydrogen atoms
 
We know,
 
1 gm of hydrogen atoms = 1 mole 
 
1 mole of hydrogen =6.022×1023 atoms
 
1 atom of hydrogen conatains 1 electron
 
Therefore 1 gm hydrogen atoms contains 6.022×1023 electrons.
 
Now, for 1 gm of oxygen atoms
 
No. of moles of oxygen
     equals 1 over 16

equals space 0.0625 space mol
 
1 mol of oxygen atoms = 6.022×1023 atoms
 
 
so 0.0625 mol f oxygen atoms = 
 
fraction numerator 0.0625 cross times space 6.022 cross times 10 to the power of 23 space end exponent over denominator 1 end fraction

equals space 3.76 space cross times 10 to the power of 22 space end exponent space atoms

1 space atom space of space oxygen space conatains space 8 space electrons space

therefore space 3.76 space cross times 10 to the power of 22 space end exponent space atoms space will space contain space space fraction numerator 3.76 space cross times 10 to the power of 22 space end exponent space cross times 8 over denominator 1 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 3.11 cross times cross times 10 to the power of 23 space end exponent space electrons
For 2 gm oxygen atoms 

No. of moles of oxygen
 
     equals 2 over 16

equals space 0.125 space mol
 
1 mol of oxygen atoms = 6.022×1023 atoms
 
so 0.125 mol f oxygen atoms = 
 
fraction numerator 0.125 cross times space 6.022 cross times 10 to the power of 23 space end exponent over denominator 1 end fraction

equals 7.5 space cross times 10 to the power of 22 space end exponent space atoms

1 space atom space of space oxygen space conatains space 8 space electrons space

therefore space 7.5 space cross times 10 to the power of 22 space end exponent space space atoms space will space contain space space fraction numerator 7.5 space cross times 10 to the power of 22 space end exponent space space cross times 8 over denominator 1 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 6.022 cross times 10 to the power of 23 space end exponent space electrons
Therefore 2 gm of oxygen atoms will conatain 6.022×1023 electrons which are same as in 1 gm hydrogen atom.
 

Answered by Varsha | 2nd May, 2019, 11:58: AM