Pls solve it.

Asked by prodyumna02 | 20th Mar, 2019, 04:15: PM

Expert Answer:

We know that hydrocarbon contains only hydrogen and carbon.
 
(a) Therefore hydrocarbon X contains hydrogen and carbon.
 
(b) The copper oxide acts as an oxidising agent.
 
(c) 
 
    (i) No. of moles of CO2 
 
 
       The volume of  CO2 = 224 ml
 
        We know,
 
         1 mole = 22400 ml
 
         So 224 ml will be 
                                    space equals space 224 over 22400

equals space 0.01 space mlo 
 
Also,
 
(ii) 22400 ml contains 12 gm of carbon
 
     That is 1 mole contains 12 g of C
 
     So 0.01 mole will contain = 0.12 g of C
 
(iii) Mass of hydrogen = total mass of hydrocarbon − mass of carbon
 
 
      mass of hydrocarbon = 0.145 g
 
 
     Mass of hydrogen = 0.145 − 0.12
 
                               = 0.025 g
 
(iv) Mass of carbon = 0.12 gm
 
     Mass of hydrogen = 0.025 g
 
    Atomic mass of carbon = 12 
 
    Atomic mass of hydrogen = 1
 
No. space of space atoms space of space Carbon space equals space fraction numerator 0.12 over denominator 12 end fraction space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.01

No. space of space atoms space of space space hydrogen space equals space fraction numerator 0.025 over denominator 1 end fraction

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 1

Simplest space ratio space equals space fraction numerator 0.025 over denominator 0.01 end fraction space

space space space space space space space space space space space space space space space space space space space space space space equals space 2.5

Simplest space ratio space equals space fraction numerator 0.01 over denominator 0.01 end fraction space

space space space space space space space space space space space space space space space space space space space space space space equals space 1
 
Multiply 2.5 and 1 by 2 to get the simplest ratio,
 
So, the empirical formula is C2H5 

Answered by Varsha | 20th Mar, 2019, 07:20: PM