Pls sol ve

Asked by pb_ckt | 11th Jun, 2019, 03:35: PM

Expert Answer:

begin mathsize 16px style fraction numerator cos 4 straight x plus cos 3 straight x plus cos 2 straight x over denominator sin 4 straight x plus sin 3 straight x plus sin 2 straight x end fraction end style
begin mathsize 16px style equals fraction numerator cos 4 straight x plus cos 2 straight x plus cos 3 straight x over denominator sin 4 straight x plus sin 2 straight x plus sin 3 straight x end fraction end style
begin mathsize 16px style equals fraction numerator 2 cos 3 xcosx plus cos 3 straight x over denominator 2 sin 3 xcosx plus sin 3 straight x end fraction end style
begin mathsize 16px style equals fraction numerator 2 cos 3 straight x open parentheses cos 3 straight x plus 1 close parentheses over denominator 2 sin 3 straight x open parentheses cos 3 straight x plus 1 close parentheses end fraction end style
= cot3x

Answered by Sneha shidid | 11th Jun, 2019, 04:18: PM