pls help

MI = MR²/2 = 2.5 kg m²

Torque = (10 N)(0.25 m) = = 2.5 N m

Torque = MI x Angular acceleration

(10 N)(0.25 m) = ((80 kg)(0.25 m)²/2) x Angular Acceleration,

Angular Acceleration = 1 rad/s²

Final Angular Velocity = Initial Angular Velocity + (Angular Acceleration)(Time)

= 5 + (1)(20) = 25 rad/s

Work done by the torque = Change in KE = I(w_f²-w_i²)/2 = 2.5(25²-5²)/2 = 750 J

Regards,

Team,

TopperLearning.