pls help

Asked by  | 28th Jul, 2009, 09:24: PM

Expert Answer:

Since the second body is released after 2s, when the first body was released and we have to find the seperation between the two bodies after the release of first body, therefore first body falls for 3s and the second for 1s.

Let S1 be the distance travelled by the first body and S2 by the second body.

so, S1 = 9.8 ( 3)2 / 2 .................................(i)

and, S2 = 9.8 (1)2 / 2 ................................(ii)

Thus the seperation between two bodies,

S = S-  S2

After substituting the values and calculating, you will find the value for seperation.

Answered by  | 30th Jul, 2009, 01:33: AM

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