pls help

Since the second body is released after 2s, when the first body was released and we have to find the seperation between the two bodies after the release of first body, therefore first body falls for 3s and the second for 1s.

Let S₁ be the distance travelled by the first body and S₂ by the second body.

so, S₁ = 9.8 ( 3)² / 2 .................................(i)

and, S₂ = 9.8 (1)² / 2 ................................(ii)

Thus the seperation between two bodies,

S = S₁ -  S₂

After substituting the values and calculating, you will find the value for seperation.