CBSE Class 9 Answered
Pls help me with this question..
Asked by supriya3020kumari | 19 Jun, 2020, 08:44: PM
Expert Answer
We need to factorise the polynomial p(x) = 6x3 - 25x2 + 32x - 12 using Remainder theorem
x - a is a factor of p(x) when the remainder is zero by dividing p(x) by x - a
Take x = 1 i.e dividing by x - 1, so the remainder would be p(1)
p(1) = 6(1)3 - 25(1)2 + 32(1) - 12 = 6 - 25 + 32 - 12 = 38 - 37 = 1 not equal to 0
Take x = 2
p(2) = 6(2)3 - 25(2)2 + 32(2) - 12 = 48 - 100 + 64 - 12 = 112 - 112 = 0
The remainder is 0
Therefore, x - 2 is the factor of p(x)
By dividing p(x) by x - 2, the quotient will be 6x2 - 13x + 6
p(x) = (x - 2)(6x2 - 13x + 6)
= (x - 2)(6x2 - 9x - 4x + 6)
= (x - 2)[3x(2x - 3) - 2(2x - 3)]
= (x - 2)(2x - 3)(3x - 2)
Answered by Renu Varma | 22 Jun, 2020, 01:02: PM
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Remainder Theorem
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