pls explain:

Asked by  | 16th Jul, 2009, 11:41: PM

Expert Answer:

the reqd plane is parallel to 2x-y+3z=-7

so it's perpendicular ro the normal to this plane.

 i.e. it's perpendicular to the line whose d.r. s are 2,-1,3.So in the standard form

a=2,b=-1,c=3

so using the point (1,4,-2) as (x1,y1,z1)

we get the equation of the reqd plane as

a(x-x1)+b(y-y1)+c(z-z1)=0

2(x1)-1(y-4)+3(z+2)=0

this is the reqd eqn.

Answered by  | 17th Jul, 2009, 08:09: AM

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