CBSE Class 12-science Answered
pls explain:
Asked by | 16 Jul, 2009, 11:41: PM
Expert Answer
the reqd plane is parallel to 2x-y+3z=-7
so it's perpendicular ro the normal to this plane.
i.e. it's perpendicular to the line whose d.r. s are 2,-1,3.So in the standard form
a=2,b=-1,c=3
so using the point (1,4,-2) as (x1,y1,z1)
we get the equation of the reqd plane as
a(x-x1)+b(y-y1)+c(z-z1)=0
2(x1)-1(y-4)+3(z+2)=0
this is the reqd eqn.
Answered by | 17 Jul, 2009, 08:09: AM
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