Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Pls explain
question image
Asked by mufeedatvp2000 | 18 Apr, 2020, 04:59: PM
answered-by-expert Expert Answer
Equivalents of H2C2O4.2H2O = Equivalents of NaOH 
 
Eq. wt of oxalic acid = equals fraction numerator Mol. space wt over denominator 2 end fraction

equals 126 over 2

equals space 63
Strength of  H2C2O4.2H2O = fraction numerator 6.3 over denominator begin display style bevelled 250 over 1000 end style end fraction space equals space 25.2 space straight g divided by straight L
 
Normality of H2C2O4.2H2O = 
 
 
equals fraction numerator Strength over denominator Eq. space wt end fraction

equals fraction numerator 25.2 over denominator 63 end fraction

equals space 0.4 space straight N
Using normality equation,
 
N1V = N2V2    
 
0.4 ×10 = 0.1 ×V2  
 
V2 = 
 
space fraction numerator 0.4 cross times 10 over denominator 0.1 end fraction

equals 40 space ml
Answered by Varsha | 18 Apr, 2020, 06:17: PM
CBSE 12-science - Chemistry
Asked by saritanohar22 | 13 Jan, 2024, 01:25: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by shamiyaali732 | 26 Sep, 2023, 02:00: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by elabarman58 | 23 Jan, 2023, 09:39: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by gauravrastogi577 | 16 Aug, 2022, 06:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by gauravrastogi577 | 16 Aug, 2022, 06:17: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by shiv.pama83 | 27 Nov, 2021, 05:50: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by mdarsadazizh | 31 Aug, 2021, 01:02: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by tejasdhaware509 | 02 Apr, 2021, 12:46: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×