pls explain asap.......

Asked by  | 24th Dec, 2009, 11:30: PM

Expert Answer:

Let x, y be the number of packets of plain biscuits and chocolate biscuits repectively.

Anyway she wants to buy 3 plain and 4 chocolate biscuits, costing 54 rupees, so we have to maximize for the remaining amount.

Maximize Z = x + y

subject to

6x + 9y ≤ 18, i.e. y ≤ -2x/3 + 2 

x≥0,

y≥0,

Plotting these we find the feasible region is just a triangle, with vertices, (0,0), (0,2), (3,0)

So (3,0) is the optimum point.

Total number of packets = 3+3 + 4 = 10.

Regards,

Team,

TopperLearning.

 

 

 

Answered by  | 25th Dec, 2009, 03:24: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.