pls explain asap.......
Asked by | 24th Dec, 2009, 11:30: PM
Let x, y be the number of packets of plain biscuits and chocolate biscuits repectively.
Anyway she wants to buy 3 plain and 4 chocolate biscuits, costing 54 rupees, so we have to maximize for the remaining amount.
Maximize Z = x + y
6x + 9y ≤ 18, i.e. y ≤ -2x/3 + 2
Plotting these we find the feasible region is just a triangle, with vertices, (0,0), (0,2), (3,0)
So (3,0) is the optimum point.
Total number of packets = 3+3 + 4 = 10.
Answered by | 25th Dec, 2009, 03:24: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number