pls answer

Asked by garimasingh | 14th Oct, 2009, 12:13: PM

Expert Answer:

It is given that triangle AED is similar to triangle BEC.

To prove: AD = BC

Proof: We know that the diagonals of trapezium cut each other in same ratio.

The above stament can also be proved by showing AEB  CED (AA corollary)

We get, EB/ DE = EA/ EC

Therefore, EB.EC = EA.ED ............(1)

Now, ΔAED  ΔBEC

We get, AE/ BE = ED/ EC

EA. EC = EB. ED ............(2)

EB = EA

⇒ ED = EC

i.e ΔAED  ΔBEC

So, AD = BC

Answered by  | 22nd Oct, 2009, 04:12: PM

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