CBSE Class 11-science Answered
pls answer quickly tuesday is exam
Asked by lausonia | 14 Mar, 2010, 09:08: PM
Expert Answer
sn = n(2a0 + (n-1)d)/2 ... first AP
and
Sn =n(2A0 + (n-1)D)/2 ... second AP.
sn/Sn = (2a0 + (n-1)d)/(2A0 + (n-1)D) = (3n+8)/(7n+15)
Put n = 23,
s23/S23 = (2a0 + 22)d)/(2A0 + 22D) = (3x23+8)/(7x23+15) = 77/176
(a0 + 11)d)/(A0 + 11D) = (3x23+8)/(7x23+15) = 77/176
a12/A12 = (a0 + 11d)/(A0 + 11D) = 77/176
Regards,
Team,
TopperLearning.
Answered by | 15 Mar, 2010, 07:51: AM
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