Asked by 2joseph | 29th Nov, 2009, 08:02: AM
if she takes x hrs originally, then now she wants to finish the task in x-(1/4)x hrs
i.e. 3x/4 hrs
so her speed must be 4/3 times the original speed.
so if the spped was y hrs, then it must now be 4y/3
so an increase of y/3 needs to be done to her speed
in y an increment of y/3 is reqd
we can find for 100 easily.
that is the percentage increase.
Answered by | 30th Nov, 2009, 08:35: AM
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