please tell
Asked by vivek1011 | 12th Sep, 2009, 11:19: PM
Expert Answer:
Assume,
L = Length of the wire,
A = Cross sectional area of the wire,
ρ = Resistivity of the wire,
R = Resistance of the wire,
R = ρL/A
R' = Resistance of 1 part = (ρL)/(5A)
1/Req = 5(1/R') = 5 (5A)/(ρL)
1/Req = (25A)/(ρL)
Req = (ρL)/(25A)
R/Req = 25
Regards,
Team,
TopperLearning.
Answered by | 13th Sep, 2009, 01:21: AM
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