Asked by | 19th Dec, 2008, 06:22: PM
let the first term be a and common difference be d.
so last three terms will be 19th,20th,21st
so a+18d + a+19d + a+20d = 237
similarly middle three terms 10th, 11th and 12th
so a+9d+a+10d+a+11d = 129
so we have two equations and two unknowns.
solve for a and d,
and A.P. will be a, a+d, a+2d, a+2d,....
Answered by | 19th Dec, 2008, 07:32: PM
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