CBSE Class 10 Answered
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Asked by | 09 Mar, 2009, 11:47: AM
Expert Answer
3 terms in the middle are 10th, 11th and 12th terms.
Hence, a+9d +a +10d +a + 11d = 129
⇒a+10d = 43 ...(1)
Last 3 terms are 19th, 20th and 21st terms
Hence, a+18d+a+19d+a+20d = 237
⇒a+19d = 79...(2)
Solving (1) and (2)
we get a = 3 and d=4
Hence, the AP is 3,7,11,15,19....83
Answered by | 09 Mar, 2009, 02:33: PM
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