CBSE Class 9 Answered
please tell fast
Asked by pranavjain | 16 Jan, 2010, 12:56: PM
Expert Answer
P(x)= x3+ax2+bx+6
remainder -3 Divisor: (x-3)
P(3)= 27+9a+3b+6 =3
3a+b+10.=0 ....(i)
P(2)=0
8+4a+2b+6=0
2a+b+7=0....(ii)
Solving (i) and (ii) we get
a=-3 b=-1
Answered by | 16 Jan, 2010, 01:09: PM
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