please tell----chemical equlibrilum
Asked by gober45 | 13th Nov, 2009, 05:35: PM
N2O4 (g) 2 NO2 (g)
Initial no. of moles 1 mole
At eqm 1 - α 2α
α = 20% of 1 mole = 0.2
Total number of moles at eqm = 1 - α + 2α = 1 + α
At the start, PV = nRT
1 * V = 1 * 0.082 * 300
V = 24.6
Now at equilibrium,
P'V = nRT
P' * 24.6 = 1.2 * 0.082 * 600
P' = 2.4 atm
Answered by | 21st Nov, 2009, 11:01: AM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change