please tell----chemical equlibrilum

Asked by gober45 | 13th Nov, 2009, 05:35: PM

Expert Answer:

                                                 N2O4 (g) 2 NO2 (g)

Initial no. of moles                      1 mole                  

At eqm                                        1 - α                   2α

α = 20% of 1 mole = 0.2

Total number of moles at eqm = 1 - α +  2α = 1 + α = 1.2

At the start, PV = nRT

1 * V = 1 * 0.082 * 300

V = 24.6

Now at  equilibrium,

P'V = nRT

P' * 24.6 = 1.2 * 0.082 * 600

P' = 2.4 atm

Answered by  | 21st Nov, 2009, 11:01: AM

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