Please someone solve

No. 15.iii)

Asked by jiujam | 6th Jul, 2019, 03:34: PM

Expert Answer:

sin2 x + sin2 (x - y) - 2sinxcosysin(x - y)
= sin2x + sin (x - y)[sin(x - y) - 2sinx cosy]
= sin2 x + sin(x - y)[sinx cosy - cosx siny - 2sinx cosy]
= sin2 x + sin(x - y)[-(sin x cos y + cos x sin y)]
= sin2 x - sin(x - y)(sin x cos y + cos x sin y)
= sin2 x - sin(x - y)sin (x + y)
= sin2 x - (sin2 x + sin2 y)
= sin2y

Answered by Renu Varma | 8th Jul, 2019, 10:21: AM