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please solve :-

Asked by | 4th Apr, 2008, 02:10: PM

Expert Answer:

Given: solubility of H2S gas = 0.195m

             It means 0.195 moles of H2S is dissolved in 1 Kg of solvent(water).







                                                                                       1000

              Solution:        1 Kg of solvent contains =-------------

                                                                                        18



                                                                             =55.5moles

                                                                                                                        n_H2S

                                      Mole fraction of H2S gas in solution ,X_H2S=

                                                                                                                     n_H2S+n_H2O



                                                                                                                      0.195

                                                                                                          =

                                                                                                                   0.195+55.55

                                                                                                             =0.0035

                                     Pressure at STP=0.987bar=1 atm



                                      p_H2S=K_H X   x_H2S





                                                            0.987

                                           K_H =

                                                       0.0035

                                                    =282bar

Answered by | 6th Jul, 2008, 11:08: AM

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