please solve :-
Asked by
| 13th Apr, 2008,
06:51: PM
Expert Answer:
here when x->1+ limit is zero because [x-1]=0 and |x-1|=0
but for x->1- limit is -1 because [x-1]=-1and |x-1|=0
so f is discontinuous at x=1
no, f cant be modified to make it continuous
Answered by
| 10th Aug, 2008,
03:38: AM
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