please solve :-

Asked by  | 13th Apr, 2008, 06:51: PM

Expert Answer:

here when x->1+ limit is zero because [x-1]=0 and |x-1|=0

but for x->1- limit is -1 because [x-1]=-1and |x-1|=0

so f is discontinuous at x=1

no, f cant be modified to make it continuous

Answered by  | 10th Aug, 2008, 03:38: AM

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