please solve

Asked by defence | 22nd Apr, 2019, 12:21: PM

Expert Answer:

G = 6.67×10-11 N m2 kg-2   .........................(1)
if we substitute, 1 N = 1 kg m s-2  in eqn.(1),
then G = 6.67×10-11 kg-1 m3 s-2  =  6.67×10-11 begin mathsize 12px style fraction numerator 1 over denominator 1 space k g cross times begin display style fraction numerator 1000 space g over denominator 1 space k g end fraction end style end fraction end style × begin mathsize 12px style 1 space m cubed cross times fraction numerator 10 to the power of 6 space c m cubed over denominator 1 space m cubed end fraction end style ×s-2 = 6.67×10-8 g-1 cm3 s-2

Answered by Thiyagarajan K | 22nd Apr, 2019, 12:45: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.