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please solve
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Asked by defence | 22 Apr, 2019, 12:21: PM
answered-by-expert Expert Answer
G = 6.67×10-11 N m2 kg-2   .........................(1)
 
if we substitute, 1 N = 1 kg m s-2  in eqn.(1),
then G = 6.67×10-11 kg-1 m3 s-2  =  6.67×10-11 begin mathsize 12px style fraction numerator 1 over denominator 1 space k g cross times begin display style fraction numerator 1000 space g over denominator 1 space k g end fraction end style end fraction end style × begin mathsize 12px style 1 space m cubed cross times fraction numerator 10 to the power of 6 space c m cubed over denominator 1 space m cubed end fraction end style ×s-2 = 6.67×10-8 g-1 cm3 s-2
Answered by Thiyagarajan K | 22 Apr, 2019, 12:45: PM

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