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CBSE Class 10 Answered

Please solve using elimination method.
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Asked by karanbora625 | 21 Apr, 2020, 08:25: AM
answered-by-expert Expert Answer
sub fraction numerator 1 over denominator 2 straight x plus 3 straight y end fraction equals straight t fraction numerator 1 over denominator 3 straight x minus 2 straight y end fraction equals straight u straight t over 2 plus fraction numerator 12 straight u over denominator 7 end fraction equals 1 half 7 straight t plus 24 straight u equals 7... open parentheses 1 close parentheses 7 straight t plus 4 straight u equals 2... open parentheses 2 close parentheses open parentheses 1 close parentheses minus open parentheses 2 close parentheses 20 straight u equals 5 straight u equals 1 fourth space space rightwards double arrow 3 straight x minus 2 straight y equals 4... open parentheses 3 close parentheses straight t equals 1 over 7 space space rightwards double arrow 2 straight x plus 3 straight y equals 7... open parentheses 4 close parentheses open parentheses 3 close parentheses cross times 2 minus open parentheses 4 close parentheses cross times 3 straight x equals 2 straight y equals 1
Answered by Arun | 22 Apr, 2020, 10:18: AM

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CBSE 10 - Maths
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