please solve this

Asked by  | 3rd Feb, 2009, 05:40: PM

Expert Answer:

for equal roots for the eqn Ax2 + Bx + C =0. the condotion is B2 = 4AC for above eqn we have A+B+C = 0                [ B = -(A+C) ]     here  A = a-b ,  B = b-c , C= c-a  so  (A+C)2 = 4AC    solving we get  A = C putting values we get  a - b = c - a

====> 2a = b+c

Answered by  | 3rd Feb, 2009, 06:51: PM

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