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CBSE Class 12-science Answered

Please solve this with full solution, or just rearranging this to a simpler form would be enough...
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Asked by Baliraja | 21 Sep, 2019, 03:58: PM
answered-by-expert Expert Answer
Markings A, B, C, D, E and F are done in the given circuit to redraw teh circuit in proper form.
 
Two resistors 12Ω and 8Ω are parallel. One end of this parallel connection is A and C .
Other end of this parallel connection is B
 
16Ω resistor is parallel to 4A current source. D and F are at one end of parallel connection. Point E is at other end.
 
B and D are coonected. E and C are connected.
 
In the redrawn circuit, it can be seen that 4A current source is directly connected to C ( left end of parallel resistors ) . 
Similarly 9A current source also directly connected C ( left end of parallel resistors ) .
 
Hence no current will flow in 16 Ω resistor , combined current of 13A flows through parallel resistors.
 
Required current i1 , i2 and i3 can be easily marked in redrawn circuit and they are shown in figure.
 
i1 = 13×(8/20) = 7.8 A  ;  i2 = 13 A  ;  i3 = 0
Answered by Thiyagarajan K | 21 Sep, 2019, 11:09: PM

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