CBSE Class 10 Answered
Please Solve this question
Asked by | 15 Aug, 2009, 03:17: PM
Expert Answer
we know that the diagonals of a parallelogram bisect each other.
it means that the point of their intersection is the mid point of each diagonal.
let the point of int. be P(q,r)
so
A,B ,C are the given three points (in the same order as in the question)
then mid point of AC is P
and
mid point of BD is P.
so, using mid point formula for AC, we get,
{[(a+b)+(a-b)]/2} ,{[(a-b)+(a+b)]/2}=(q,r)
solving we get,
p=a, q=a
now using the midpoint formula for BD we get
[x+(2a+b)]/2 ,[y+(2a-b)]/2=(a,a)
solving we get
x= -b, y=b
Answered by | 16 Aug, 2009, 10:15: AM
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