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CBSE Class 9 Answered

Please solve this problem with proper explanation 
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Asked by adityaahuja099 | 11 Dec, 2017, 08:53: PM
answered-by-expert Expert Answer
begin mathsize 16px style fraction numerator 0.83 cross times 0.83 cross times 0.83 plus 0.17 cross times 0.17 cross times 0.17 over denominator 0.83 cross times 0.83 minus 0.83 cross times 0.17 plus 0.17 cross times 0.17 end fraction Let space straight a equals 0.83 space and space straight b equals 0.17 Then comma space the space given space expression space becomes fraction numerator straight a cross times straight a cross times straight a plus straight b cross times straight b cross times straight b over denominator straight a cross times straight a minus straight a cross times straight b plus straight b cross times straight b end fraction equals fraction numerator straight a cubed minus straight b cubed over denominator straight a squared minus ab plus straight b squared end fraction equals fraction numerator left parenthesis straight a plus straight b right parenthesis left parenthesis straight a squared minus ab plus straight b squared right parenthesis over denominator straight a squared minus ab plus straight b squared end fraction equals straight a plus straight b equals 0.83 plus 0.17 equals 1.00 end style
Answered by Rashmi Khot | 12 Dec, 2017, 09:50: AM

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