Please solve the sum.
Asked by sunil_0010 | 1st Jul, 2009, 10:41: PM
Expert Answer:
for this A.P.,
a=first erm=7 yrs
d=common diff=3 months=1/4 yrs
let there be n students
So sum of their ages
=n/2[2a+(n-1)d]
=n/2[14+{(n-1)/4}]
=250(given)
so solving we get,
(n+80)(n-25)=0
so
n=25
Answered by | 1st Jul, 2009, 11:01: PM
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