CBSE Class 10 Answered
Please solve the question of linear equation by elimination method
11x+15y+23=0, 7x-2y-20=0
Asked by rameshkeethukannur | 22 Mar, 2019, 12:46: AM
11 x + 15 y = -23 ..........................(1)
7 x - 2 y = 20 ..............................(2)
eqn.(1) × 2 gives, 22 x + 30 y = -46 .....................(3)
eqn.(2) x 15 gives, 105 x - 30 y = 300 ...................(4)
By adding (3) and (4), we get 127 x = 254 or x =2
By substituting x = 2 in eqn.(1), 11 (2) + 15 y = -23 or 15 y = -23 -22 = -45 or y = -3
Hence solution of eqn.(1) and (2) is, x = 2 and y = -3
Answered by Thiyagarajan K | 22 Mar, 2019, 11:13: AM
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