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CBSE Class 12-science Answered

please solve the question in the picture.
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Asked by rohitraman1115 | 13 Jan, 2019, 01:26: PM
answered-by-expert Expert Answer
Work done by external force = q× change in potential 
                                                   =  - q ×kQ×(fraction numerator 1 over denominator x 2 end fraction minus fraction numerator 1 over denominator x 1 end fraction)
                                W= kQq(fraction numerator 1 over denominator x 1 end fraction minus fraction numerator 1 over denominator x 2 end fraction)
Answered by Ankit K | 13 Jan, 2019, 09:09: PM
CBSE 12-science - Physics
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DNa
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