Please solve the question given in the description
Asked by mac12303190 | 6th Jan, 2010, 08:46: PM
Say h= 150-x meters
Consider angle at B
tan5= opposite side / adjacent side= x / 1200 = 0.0875
x= 0.0875 X 1200=105 m.
Now consider angle at C
tan 5= x/DF =(AD-CF) / (DF) =0.0875
DF= (150-20) / 0.0875= 1485.7 m= 1.4857 Km
Since the 20stair building is at athe city centre DE is the distance if the tower from the city centre
Regards
Topperlearning Team
Answered by | 7th Jan, 2010, 10:12: AM
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