please solve the numericals:
Asked by bhimaasman | 9th Dec, 2009, 11:59: AM
Dear Student
Above critical angle there will be complete internal reflection
Q1)
If Ctitical angle =θc
Sin θc = n2/n1 Wheren1 n2 are more and les dense midium's refractive indeces respectively
In our case n1=1 (Air), n2 =1.33 (water)
Sin θc = n2/n1 =1/1.33 =0.752 ===> θc= 48.70
So, Radius of the illuminated region= Pond Depth X Sin θc = 0.752 h
Q2)
when viewed normally there is oil of length 10cm and after that water if lenght 10 cm
Opticl path length = length/ Refractive ingex = 10/1.4 + 10/1.33 = 14.66 cm
appt. depth of the tank when viewed normally = 14.66cm
Regards
Team
Topperlearning
Answered by | 12th Jan, 2010, 07:38: PM
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