CBSE Class 11-science Answered
Please solve the numerical
Asked by sukhmaneet | 01 Sep, 2009, 06:43: PM
Expert Answer
The component of weight parallel to the inclined plane, W = mgsin30 = mg/2
The component of weight perpendicular to the inclined plane, i.e. normal reaction, W = mgcos30 = 3mg/2
The kinetic friction force = μW
F = ma
W - μW = ma
mg/2 - μ3mg/2 = mg/4
1/2 - μ3/2 = 1/4
μ = 1/23 = 0.28
Regards,
Team,
TopperLearning.
Answered by | 01 Sep, 2009, 09:31: PM
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