Please solve the following

 

Asked by tultuldutta58 | 8th Jan, 2018, 01:50: AM

Expert Answer:

begin mathsize 16px style Given space equations space are space as space follows colon
ax plus by minus 1 equals 0
bx plus ay minus fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction equals 0
By space cross minus multiplication comma space we space have
fraction numerator straight x over denominator straight b open parentheses negative begin display style fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction end style close parentheses minus straight a open parentheses negative 1 close parentheses end fraction equals fraction numerator negative straight y over denominator straight a open parentheses negative begin display style fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction end style close parentheses minus straight b open parentheses negative 1 close parentheses end fraction equals fraction numerator 1 over denominator straight a open parentheses straight a close parentheses minus straight b open parentheses straight b close parentheses end fraction
rightwards double arrow fraction numerator straight x over denominator begin display style fraction numerator straight a cubed minus ab squared over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator negative straight y over denominator begin display style fraction numerator negative straight a squared straight b plus straight b cubed over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator 1 over denominator straight a squared minus straight b squared end fraction
rightwards double arrow fraction numerator straight x over denominator begin display style fraction numerator straight a left parenthesis straight a squared minus straight b squared right parenthesis over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator negative straight y over denominator begin display style fraction numerator straight b open parentheses straight a squared minus straight b squared close parentheses over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator 1 over denominator straight a squared minus straight b squared end fraction
rightwards double arrow straight x equals fraction numerator straight a over denominator straight a squared plus straight b squared end fraction space and space straight y equals fraction numerator straight b over denominator straight a squared plus straight b squared end fraction end style

Answered by Rashmi Khot | 9th Jan, 2018, 01:04: PM