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CBSE Class 10 Answered

Please solve the following  
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Asked by tultuldutta58 | 08 Jan, 2018, 01:50: AM
answered-by-expert Expert Answer
begin mathsize 16px style Given space equations space are space as space follows colon ax plus by minus 1 equals 0 bx plus ay minus fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction equals 0 By space cross minus multiplication comma space we space have fraction numerator straight x over denominator straight b open parentheses negative begin display style fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction end style close parentheses minus straight a open parentheses negative 1 close parentheses end fraction equals fraction numerator negative straight y over denominator straight a open parentheses negative begin display style fraction numerator 2 ab over denominator straight a squared plus straight b squared end fraction end style close parentheses minus straight b open parentheses negative 1 close parentheses end fraction equals fraction numerator 1 over denominator straight a open parentheses straight a close parentheses minus straight b open parentheses straight b close parentheses end fraction rightwards double arrow fraction numerator straight x over denominator begin display style fraction numerator straight a cubed minus ab squared over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator negative straight y over denominator begin display style fraction numerator negative straight a squared straight b plus straight b cubed over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator 1 over denominator straight a squared minus straight b squared end fraction rightwards double arrow fraction numerator straight x over denominator begin display style fraction numerator straight a left parenthesis straight a squared minus straight b squared right parenthesis over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator negative straight y over denominator begin display style fraction numerator straight b open parentheses straight a squared minus straight b squared close parentheses over denominator straight a squared plus straight b squared end fraction end style end fraction equals fraction numerator 1 over denominator straight a squared minus straight b squared end fraction rightwards double arrow straight x equals fraction numerator straight a over denominator straight a squared plus straight b squared end fraction space and space straight y equals fraction numerator straight b over denominator straight a squared plus straight b squared end fraction end style
Answered by Rashmi Khot | 09 Jan, 2018, 01:04: PM

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