Please solve the following

Asked by Balbir | 6th Oct, 2017, 12:14: PM

Expert Answer:

begin mathsize 16px style In space the space type space of space integral fraction numerator dx over denominator asinx space plus space bcosx space plus space straight c end fraction
we space always space use space the space method space like space this colon
tan straight x over 2 space equals space straight t
straight x over 2 equals space tan to the power of negative 1 end exponent space straight t
straight x space equals space 2 space tan to the power of negative 1 end exponent space straight t
dx space equals space fraction numerator 2 over denominator 1 space plus space straight t squared end fraction dt space
sinx space equals space fraction numerator 2 tan straight x over 2 over denominator 1 plus tan squared straight x over 2 end fraction equals fraction numerator 2 straight t over denominator 1 plus straight t squared end fraction
cosx space equals space fraction numerator 1 minus tan squared straight x over 2 over denominator 1 plus tan squared straight x over 2 end fraction equals fraction numerator 1 minus straight t squared over denominator 1 plus straight t squared end fraction
Put space it space in space the space question space and space solve space it space further. end style

Answered by Sneha shidid | 22nd Dec, 2017, 09:46: AM