Please solve the following question

Asked by Balbir | 7th Oct, 2017, 11:17: PM

Expert Answer:

begin mathsize 16px style integral fraction numerator straight x squared space plus space sin squared straight x over denominator 1 plus straight x squared end fraction cross times sec squared xdx
integral fraction numerator straight x squared plus 1 minus 1 plus sin squared straight x over denominator 1 plus straight x squared end fraction cross times sec squared straight x dx
integral fraction numerator straight x squared plus 1 minus open parentheses 1 minus sin squared straight x close parentheses over denominator 1 plus straight x squared end fraction cross times sec squared straight x dx
integral open parentheses fraction numerator straight x squared plus 1 over denominator straight x squared plus 1 end fraction minus fraction numerator 1 minus sin squared straight x over denominator 1 plus straight x squared end fraction close parentheses sec squared straight x dx
integral open parentheses 1 minus fraction numerator begin display style cos squared end style begin display style straight x end style over denominator 1 plus straight x squared end fraction close parentheses sec squared xdx
integral open parentheses sec squared straight x minus fraction numerator begin display style cos squared straight x cross times sec squared straight x end style over denominator 1 plus straight x squared end fraction close parentheses dx
integral open parentheses sec squared straight x minus fraction numerator begin display style 1 end style over denominator 1 plus straight x squared end fraction close parentheses dx
Further space you space can space integhrate space using space formulae. end style

Answered by Sneha shidid | 18th Dec, 2017, 11:20: AM