CBSE Class 12-science Answered

Please solve the following question

Asked by Balbir | 07 Oct, 2017, 11:11: PM

Expert Answer

begin mathsize 16px style integral fraction numerator square root of straight x squared plus straight a squared end root over denominator straight x end fraction dx integral fraction numerator square root of straight x squared plus straight a squared end root over denominator straight x end fraction cross times fraction numerator square root of straight x squared plus straight a squared end root over denominator square root of straight x squared plus straight a squared end root end fraction dx integral fraction numerator straight x squared plus straight a squared over denominator straight x square root of straight x squared plus straight a squared end root end fraction dx integral open parentheses fraction numerator straight x squared over denominator straight x square root of straight x squared plus straight a squared end root end fraction plus fraction numerator straight a squared over denominator straight x square root of straight x squared plus straight a squared end root end fraction close parentheses dx For space the space first space integral space put space straight x squared plus straight a squared space equals space straight t and space for space second space integral space put space straight x space equals space 1 over straight z Solve space it space further. We space appreciate space if space you space solve space it space and space send space snapshot space of space your space work. end style

Answered by Sneha shidid | 21 Dec, 2017, 03:19: PM

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