Please solve the following question

Asked by Balbir | 7th Oct, 2017, 11:15: PM

Expert Answer:

begin mathsize 16px style integral fraction numerator square root of cos 2 straight x end root over denominator cosx end fraction dx
integral fraction numerator square root of begin display style fraction numerator 1 minus tan squared straight x over denominator 1 plus tan squared straight x end fraction end style end root over denominator cos begin display style straight x end style end fraction dx
integral fraction numerator square root of begin display style fraction numerator 1 minus tan squared straight x over denominator sec squared straight x end fraction end style end root over denominator cos begin display style straight x end style end fraction dx
integral fraction numerator square root of 1 minus tan squared straight x end root over denominator secx cross times cosx end fraction dx
integral fraction numerator square root of 1 minus tan squared straight x end root over denominator 1 end fraction dx
put space tan space straight x space equals space sint
and space solve space it space further.
end style

Answered by Sneha shidid | 21st Dec, 2017, 03:17: PM