CBSE Class 10 Answered
please solve it!!!!!!!!!!!!!!!!!!!!
Asked by kriscisf | 17 Nov, 2008, 08:35: PM
Expert Answer
.jpg)
as stated in the question
ADB = 30 and ACB =60
so tan30 = AB / BD and tan60 = AB / BC
let the speed of car be v then BD-BC =6v
put the values of BC and BD
2AB / 
3 = 6v
now car has to travel BC to reach the foot of the tower.
so it will take BC/ v sec to reach there.
which is AB / v = 33
put value of AB=BC3
BC / v = 3 sec.
v= AB / 33
Answered by | 29 Nov, 2008, 03:50: AM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT
