please solve it sir

 

Asked by satishkashyap02022004 | 29th Apr, 2020, 03:07: PM

Expert Answer:

Mean orbital radius of Sun = 1.5 × 108 km = 1.5 × 1011 m 
 
 
T h e space p e r i o d space o f space t h e space E a r t h space a r o u n d space t h e space S u n space i s space equals space 1 space y e a r space equals space 356 space d a y s space equals space 365 space cross times space 24 cross times space 60 cross times 60 space s e c o n d s T h e space t i m e space p e r i o d space o f space p l a n e t s space m o v i n g space a r o u n d space S u n space i s space g i v e n space a s comma space T space equals space 2 pi square root of fraction numerator r cubed over denominator G M subscript S u n end subscript end fraction end root T h u s comma space T squared space equals space fraction numerator 4 pi squared r cubed over denominator G M subscript S u n end subscript end fraction space M subscript S u n end subscript space equals space fraction numerator 4 pi squared r cubed over denominator G T squared end fraction space therefore space M subscript S u n end subscript space equals space space fraction numerator 4 open parentheses 3.14 close parentheses squared cross times open parentheses 1.5 cross times 10 to the power of 11 close parentheses cubed over denominator 6.67 cross times 10 to the power of negative 11 end exponent space cross times space open parentheses space 365 space cross times space 24 cross times space 60 cross times 60 close parentheses squared end fraction space M subscript S u n end subscript space almost equal to space 2 cross times 10 to the power of 30 space k g space

Answered by Shiwani Sawant | 29th Apr, 2020, 06:15: PM

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