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CBSE Class 12-science Answered

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Asked by rd0543293 | 19 Jun, 2022, 10:51: AM
Expert Answer
I1 = I2 = 10 A 
d = 2 m 
Force per unit length is given as, 
F equals space fraction numerator mu subscript 0 I subscript 1 I subscript 2 over denominator 2 pi d end fraction space equals space fraction numerator 4 pi cross times 10 to the power of negative 7 end exponent cross times 10 space cross times space 10 over denominator 2 cross times pi cross times 2 end fraction equals 10 to the power of negative 5 end exponent space N divided by m space
As the current flows in same direction there will be attractive force between the two wires. 
Answered by Shiwani Sawant | 20 Jun, 2022, 01:25: PM
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